1.输入两个数按从小到大的顺序排列
#include <stdio.h>
int main() {
int a, b, t;
printf("input a,b: ");
scanf("%d,%d", &a, &b);
if (a > b) {
t = a;
a = b;
b = t;
}
printf("output: %d,%d", a, b);
return 0;
}
输出:
/Users/wuyanbo/Documents/ClionProject/cmake-build-debug/ClionProject
input a,b: 2，1
output: 1，2
Process finished with exit code 0
2.输入3个整数把最大的输出
#include <stdio.h>
int main() {
int a, b, c, max;
printf("input a,b,c: ");
scanf("%d,%d,%d", &a, &b, &c);
max = a;
if (max < b)
max = b;
if (max < c)
max = c;
printf("max=%d", max);
return 0;
}
输出:
/Users/wuyanbo/Documents/ClionProject/cmake-build-debug/ClionProject
input a,b,c: 1,2,3
max=3
Process finished with exit code 0
3.输入3个整数按从小到大的顺序打印
#include <stdio.h>
int main() {
int a, b, c, t;
printf("input a,b,c: ");
scanf("%d,%d,%d", &a, &b, &c);
if (a > b) {
t = a;
a = b;
b = t;
}
if (a > c) {
t = a;
a = c;
c = t;
}
if (b > c) {
t = b;
b = c;
c = t;
}
printf("%d,%d,%d\n", a, b, c);
return 0;
}
输出：
/Users/wuyanbo/Documents/ClionProject/cmake-build-debug/ClionProject
input a,b,c: 2,1,3
1,2,3
Process finished with exit code 0
4.判断是否为闰年
#include <stdio.h>
int main() {
int year;
printf("input a year: ");
scanf("%d", &year);
if (year % 4 == 0 && year % 100 != 0 || year % 400 == 0)
printf("%d is a leap year\n", year);
else
printf("%d is a not leap year\n", year);
return 0;
}
输出：
/Users/wuyanbo/Documents/ClionProject/cmake-build-debug/ClionProject
input a year: 2018
2018 is a not leap year
Process finished with exit code 0
5.输入一个字符，如果是大写字母，则转换为小写，否则不转换并输出最后得到的字符
#include <stdio.h>
int main() {
char letter;
printf("input leeter: ");
scanf("%c", &letter);
if ('A' <= letter && letter <= 'Z')
letter = letter + 32;
printf("letter: %c", letter);
return 0;
}
输出：
/Users/wuyanbo/Documents/ClionProject/cmake-build-debug/ClionProject
input leeter:A
letter: a
Process finished with exit code 0
6.编程求解:
/-1 (x<0)
y=| 0 (x=0)
\ 1 (x>0)
1).
#include <stdio.h>
int main() {
int x, y;
printf("input x: ");
scanf("%d", &x);
if (x < 0)
y = -1;
else if (x == 0)
y = 0;
else
y = 1;
printf("y=%d", y);
return 0;
}
2).
#include <stdio.h>
int main() {
int x, y;
printf("input x: ");
scanf("%d", &x);
y = -1;
if (x != 0)
if (x > 0)
y = 1;
else
y = 0;
printf("y=%d", y);
return 0;
}
3).
#include <stdio.h>
int main() {
int x, y;
printf("input x: ");
scanf("%d", &x);
if (x >= 0)
if (x > 0)
y = 1;
else
y = 0;
else
y = -1;
printf("y=%d", y);
return 0;
}
输出：
/Users/wuyanbo/Documents/ClionProject/cmake-build-debug/ClionProject
input x: 12
y=1
Process finished with exit code 0
7.按成绩分档次（A,B,C,D,E）
1).
#include <stdio.h>
int main() {
int score;
char grade;
printf("input score： ");
scanf("%d", &score);
if (score >= 90)
grade = 'A';
else if (score >= 80)
grade = 'B';
else if (score >= 70)
grade = 'C';
else if (score >= 60)
grade = 'D';
else
grade = 'E';
putchar(grade);
return 0;
}
2).
#include <stdio.h>
int main() {
int score;
char grade;
printf("input score： ");
scanf("%d", &score);
switch (score / 10) {
case 10:
case 9:
grade = 'A';
break;
case 8:
grade = 'B';
break;
case 7:
grade = 'C';
break;
case 6:
grade = 'D';
break;
default:
grade = 'E';
break;
}
putchar(grade);
return 0;
}
输出：
/Users/wuyanbo/Documents/ClionProject/cmake-build-debug/ClionProject
input score： 97
A
Process finished with exit code 0
8. 编程计算1+2+3+...+100=？
1).
#include <stdio.h>
int main() {
int sum = 0, i = 1;
while (i <= 100) {
sum = sum + i;
i++;
}
printf("sum=%d\n", sum);
return 0;
}
2).
#include <stdio.h>
int main() {
int sum = 0, i = 1;
do {
sum=sum+i;
i++;
} while (i <= 100);
printf("sum=%d\n", sum);
return 0;
}
3).
#include <stdio.h>
int main() {
int sum = 0;
for (int i = 1; i <= 100; i++)
sum += i;
printf("sum=%d\n", sum);
return 0;
}
输出：
/Users/wuyanbo/Documents/ClionProject/cmake-build-debug/ClionProject
sum=5050
Process finished with exit code 0
9.计算2+4+6+...+100=?
#include <stdio.h>
int main() {
int sum = 0;
for (int i = 100; i >= 1; i -= 2)
sum += i;
printf("sum=%d\n", sum);
return 0;
}
输出：
/Users/wuyanbo/Documents/ClionProject/cmake-build-debug/ClionProject
sum=2550
Process finished with exit code 0
10.计算1+3+5+...+99=?
#include <stdio.h>
int main() {
int sum = 0;
for (int i = 1; i <= 100; i += 2)
sum += i;
printf("sum=%d\n", sum);
return 0;
}
输出：
/Users/wuyanbo/Documents/ClionProject/cmake-build-debug/ClionProject
sum=2500
Process finished with exit code 0
11.计算123*...*10=?
1).
#include <stdio.h>
int main() {
int fact = 1, k = 1;
while (k <= 10) {
fact = fact * k;
k++;
}
printf("fact=%d\n", fact);
return 0;
}
2).
#include <stdio.h>
int main() {
int fact = 1;
for (int k = 1; k <= 10; k++) {
fact *= k;
}
printf("fact=%d\n", fact);
return 0;
}
输出：
/Users/wuyanbo/Documents/ClionProject/cmake-build-debug/ClionProject
fact=3628800
Process finished with exit code 0
12.1~100之间所有自然数平方和
#include <stdio.h>
int main() {
int sum = 0;
for (int i = 1; i <= 100; i++)
sum = sum + i * i;
printf("sum=%d\n", sum);
return 0;
}
输出：
/Users/wuyanbo/Documents/ClionProject/cmake-build-debug/ClionProject
sum=338350
Process finished with exit code 0
13.1~100之间能被3整除的数之和
#include <stdio.h>
int main() {
int sum = 0;
for (int i = 1; i <= 100; i++)
if (i % 3 == 0)
sum += i;
printf("sum=%d\n", sum);
return 0;
}
输出：
/Users/wuyanbo/Documents/ClionProject/cmake-build-debug/ClionProject
sum=1683
Process finished with exit code 0
14.从键盘上输入一串字符，分别将字母和数字以及其他字符做统计并输出
#include <stdio.h>
int main() {
int letter = 0, digit = 0, other = 0;
char ch;
while ((ch = getchar()) != '!') {
if (ch >= 'a' && ch <= 'z' || ch >= 'A' && ch <= 'Z')
letter++;
else if (ch >= '0' && ch <= '9')
digit++;
else
other++;
}
printf("letter:%d\ndigit:%d\nother:%d\n", letter, digit, other);
return 0;
}
/Users/wuyanbo/Documents/ClionProject/cmake-build-debug/ClionProject
sdhjashjdhasjh3112312JDHSAJDKJSDJ!
letter:26
digit:7
other:0
Process finished with exit code 0
15.从键盘上输入一串字符，要求判断每一个字符，大写字母转成小写字母，小写字母转换成大写字母，其他不变并输出
#include <stdio.h>
int main() {
char ch;
while ((ch = getchar()) != '!') {
if (ch >= 97 && ch <= 122)
ch -= 32;
else if (ch >= 65 && ch <= 90)
ch += 32;
putchar(ch);
}
return 0;
}
输出：
/Users/wuyanbo/Documents/ClionProject/cmake-build-debug/ClionProject
sdjkasdjkasjjdkdJSDAKDJAKSJ2321312!
SDJKASDJKASJJDKDjsdakdjaksj2321312
Process finished with exit code 0
